The mole fraction of component A in vapour phase is `y_1,` and mole fraction of component A in liquid mixture is `x_1 (P_A^@ "=vapour pressure of pure A, P"_B^@="vapour pressure of pure B").` Then total vapour pressure of the liquid mixture is

Options

A. `(P_(A)^(@)x_(1))/(y_(1))`
B. `(P_(A)^(@)y_(1))/(x_(1))`
C. `(P_(B)^(@)y_(1))/(x_(1))`
D. `(P_(B)^(@)x_(1))/(y_(1))`

Answer

A

Explanation

`P_(A)= P_(A)^(@) x_(1)`
Mole fraction of A in vapour `= (P_(A))/(P_("Total"))`
`y_(1)= (P_(A)^(@)x_(1))/(P_("total")) therefore P_("total") =(P_(A)^(@) x_(1))/(y_(1))`