The relative decrease in the vapour pressure of an aqueous solution containing 2 mol `[Cu(NH)_3CI]Cl` in 3 mol `H_2O` is 0.50. On reaction with `AgNO_3,` this solution will form a)1 mol AgCl b)0.25 mol AgCl c)2 mol AgCl d)0.40 mol AgCl

Options

A. 1mol AgCl
B. 0.25mol AgCl
C. 2mol AgCl
D. 0.40 mol AgCl

Answer

A

Explanation

`(Delta P)/(P^(@))= 0.50 = (n_(1)i)/(n_(1)i+ n_(2))`
degree of dissociation `alpha= (i-1)/(1)= 0.5`
`0.50= (2i)/(2i+3), i=1.5 =1 +x, x= 0.5`
Hence, 2 mol complex produce 1 mol unionised complex, 1 mol `Cl^(-)` ion and 1 mol cation. 1 mol `Cl^(-)` ion produces 1 mol AgCl.