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A mixture of volatile components A and B...

A mixture of volatile components A and B has total vapour pressure (in torr) `P=254-119 chi_(A)`
where `chi_(A)` is the mole fraction of Ain mixture. Hence, `P_(A)^@ and P_(B)^@` are (torr)

A

254119

B

119254

C

135254

D

154119

Text Solution

Verified by Experts

The correct Answer is:
C
`P_("total") = P_(A)^(@) chi_(A) + P_(B)^(@) chi_(B)= P_(A)^(@) chi_(A) + P_(B)^(@) chi_(A) + P_(B)^(@) (1-chi_(A)) =P_(B)^(@)- (P_(B)^(@)- P_(A)^(@))chi_(A)`
Given equation `=254-119chi_(A)`
Compare with the given equation, `therefore P_(B)^(@)= 254, P_(B)^(@)- P_(A)^(@)= 119 therefore P_(A)^(@)= 254-119=135`
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