184 g ethyl alcohol is mixed with 72 gof water. The ratio of mole fraction of alcohol to water is

Options

A. `3:4`
B. `1:2`
C. `1:4`
D. `1:1`

Answer

D

Explanation

Number of moles of `C_(2)H_(5)OH = (184)/(46)=4, (M_(C_(2)H_(5)OH)= 46g//mol)`
Number of moles of `H_(2)O= (72)/(18)=4, (M_(H_(2)O)= 18g//mol)`
Mole fraction, `X_(C_(2)H_(5)OH)= (4)/(4+4)= (4)/(8)`
`x_(H_(2)O)= (4)/(4+4)= (4)/(8)`
`rArr (x_(C_(2)H_(5)OH))/(x_(H_(2)O))= (4//8)/(4//8)= (1)/(1)= 1:1`