The density (in gmL) of a 3.60 M sulphur...

The density (in gmL) of a 3.60 M sulphuric acid solution, that is, 29% `H_2SO_4 ("molar mass=98 g mol"^(-1))` by mass will be

`1.45`

`1.64`

`1.88`

`1.22`

Text Solution

Verified by Experts

The correct Answer is:

Density, molarity and % of solution are related as molarity `=(10xx % "density")/("mol.mass")`
Substituting `(10 xx 29 xx d)/(98)=3.6 rArr d= 1.22gL^(-1)`

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