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Lowering of vapour pressure in 1 molal a...

Lowering of vapour pressure in 1 molal aqueous solution of non volatile non electrolyte solute at `100^@C` is:

A

13.44mmHg

B

14.12mmHg

C

31.2mmHg

D

35.2mmHg

Text Solution

Verified by Experts

The correct Answer is:
A
1molal solution contain 1 mole solute in 1000g water mole fraction of solute `= (1)/(1+55.56)= 0.0176`
`(P_(A)^(@)-P_(S))/(P_(A)^(@))=0.0176`
`P_(A)^(@)- P_(S)= 0.0176 xx 760 = 13.4 mm Hg`
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