A solution containing 100g ethylene glycol in 500g water is cooled to `-6.2^@C.` The amount of ice that will separate out will be `(K_f "for water=1.86K kg mol"^(-1))`

Options

A. 100.8g
B. 38.7g
C. 16.1g
D. 41.1g

Answer

C

Explanation

Let the amount of water remaining after separating out ice = `W_(A)`
The freezing point of this solution = `-6.2^(@)C`
`Delta T_(f)= (1000xx k_(f) W_(B))/(W_(A) xx M_(B)) , W_(A) = (1000xx 1.86 xx 100)/(6.2 xx 62)= 483.9g`
ice separate `=500-483.9= 16.1g`