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The depression in freezing point for 1M ...

The depression in freezing point for 1M urea, 0.5M glucose, 1M NaCl, and `1M K_(2)SO_(4)` are in the ratio `x: 1:y:z`. The value of x+z is ….

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The correct Answer is:
4
The depression in freezing point is given by `Delta T_(f)= iK_(b)m`
For the given solutions, value of i is
1M Urea 1, 1M glucose =1, 1 M NaCL =2, M `K_(2)SO_(4)=3`
Ratio of depression in freezing point is `1:1: 2:3` Therefore in `x: 1: y: z, x+ z= 1+ 3= 4`
Ratio of depression in freezing point is `1:1:2:3`. Therefore in `x:1:y:z, x+ z= 1+ 3=4`
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