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A compound H(2)X with molecular weight 8...

A compound `H_(2)X` with molecular weight 80 is dissolved in a solvent having densit 0.4 g/mL. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

Text Solution

Verified by Experts

The correct Answer is:
8
Volume of solvent = Volume of solution
Mass of one litre solvent `=100xx 0.4= 400g or 0.4kg`
Molality `= ("Number of moles of solute")/("Mass of solvent in kg")= (3.2)/(0.4) =8`
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