Home
Class 12
CHEMISTRY
Statement 1: If more and more solute is ...

Statement 1: If more and more solute is dissolved in a certain amount of solvent, the freezing point of the solution keeps on reducing.
Statement 2 Presence of large amount of dissolved non volatile solute does not allow the solution to freeze.

A

Statement 1 is True, Statement 2 is true, Statement 2 is correct explanation for Statement 1

B

Statement 1 is True, Statement 2 is True, Statement 2 is NOT a correct explanation for Statement 1

C

Statement 1 is True, Statement 2 is False

D

Statement 1 is False, Statement 2 is True

Text Solution

Verified by Experts

The correct Answer is:
C
The freezing point keeps on becoming lower and lower. Depression in freezing point is a colligative property as it depends on the number of particles present in the solution. The solution will freeze at lower temperature on adding larger amount of solute.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    BRILLIANT PUBLICATION|Exercise Level-III (Linked Comprehension Type)|12 Videos

  • SOLUTIONS

    BRILLIANT PUBLICATION|Exercise Level-III (Matching Column Type)|5 Videos

  • SOLID STATE

    BRILLIANT PUBLICATION|Exercise LEVEL-3 (Linked Comprehension Type)|10 Videos

  • STEREOCHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-II (ASSERTION - REASON TYPE)|2 Videos

Similar Questions

Explore conceptually related problems

Statement 1: When a copper wire is dipped in silver nitrate solution, there is no change in the colour of the solution. Statement 2: Copper cannot displace silver from its salt solution

Given below are some solutions. Identify and write down the solvent and the solute present in them. (Hint: Those present in large amount is the solvent and that in small amount is the solute).

Assertion : If a liquid solute more volatile than the solvent is added to the solvent, the papour pressure of the solution may increase i.e. p_s gt p^@. Reason In the presence of a more volatile liquid solute, only the solute will form the vapours and solvent will not.

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boilling point of solution was found to be 100.5^(0)C . K_(b) for H_(2)O is

Equal weight of a certain non volatile non electrolyte solute is dissolved in equal weight of two solvents A and B to form very dilute solution. The relative lowering of vapour pressure for solution B is twice the relative lowering ofvapour pressure for solution A. M_A and M_B are the molecular mass of solvents A and Brespectively, then: a)M A = M B b)M B = 2 × M A c)M A = 4 M B d)M A = 2 M B

Assertion : Larges the value of cryoscopic constant of the solvent lesser will be the freezing point of the solution Reason : Depression in the freezing point depends on the nature of the solvent. a)If both (A) and (R) are correct and (R) is the correct explanation of(A). b)If both (A) and (R) are correct, but (R) is not the correct explanation of (A). c)If (A) is correct, but (R) is incorrect. d)If both (A) and (R) are incorrect.

0.2 molal aqueous solution of acid HX is 20% ionised. K_f="1.86 K molal"^(-1) . The freezing point of the solution is very close to:

Assertion : Higher the value of molal depression constant of solvent (K) used to prepare the solution, lower will be the freezing point of the solution. Reason : Depression in freezing point depends upon the nature of the solvent. a)If both (A) and (R) are correct and (R) is the correct explanation of(A). b)If both (A) and (R) are correct, but (R) is not the correct explanation of (A). c)If (A) is correct, but (R) is incorrect. d)If both (A) and (R) are incorrect.