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The rate law expression of a reaction 2...

The rate law expression of a reaction `2A+B rarr A_(2)B` is rate =`k[A][B]^(2)` with rate constant k =0.65 `mol^(-1) L s^(-1)`
calculate rate of reaction when concentration of A has been reduced to `1//4` and concentration of B has been reduced by `1//4`

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`[A] = (1)/(4) xx 0.25 mol L^(-1) = 0.0625 mol L^(-1)` and `[B] = (1-(1)/(4)) xx 1.84 mol L^(-1) = 1.38 mol L^(-1)`
Rate `=k[A]^(2) = 0.65 mol^(-1) L s^(-1) xx (0.0625 mol^(-1) L s^(-1)) xx (0.0625 mol L^(-1))^(2) = 0.002539 mol L^(-1)s^(-1)`
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