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The rate constant for the reaction, 2N(2...

The rate constant for the reaction, `2N_(2)O_(5) rarr 4NO_(2) +O_(2)` is `3.0 xx10^(-5) s^(-1)` If the rate is `2.40 xx10^(-5)` mo `L^(-1) S^(-1)` then the concentration of `N_(2)O_(5)` (in mo `L^(-1)`) is

A

`1.4`

B

`1.2`

C

`0.04`

D

`0.8`

Text Solution

Verified by Experts

`[N_(2)O_(5)] = r//k = (2.4 xx 10^(-5) mol L^(-1)s^(-1))//(3.0 xx 10^(-5)s^(-1)) = 0.8 mol L^(-1)`
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