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For the reaction system: 2NO(g) + O(2) (...

For the reaction system: `2NO(g) + O_(2) (g) rarr 2NO_(2)` (g) volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first-order with respect to `O_(2)` and second-order with respect to NO, the rate of reaction will be

A

diminished to one-fourth of its initial value

B

diminished to one-eighth of its initial value

C

increased to eight times of its initial value

D

increased to four times of its initial value

Text Solution

Verified by Experts

The rate law for the reaction `= k[O_(2)][NO]^(2)`.
When volume is reduced to half, concentration becomes double the initial concentration, so the rate law becomes rate `= k[2O_(2)][2NO]^(2) rArr` rate `= 8k[O_(2)][NO]^(2)`
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