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The time t(1//4) can be taken as the tim...

The time `t_(1//4)` can be taken as the time taken for the concentration of a reactant to drop to 3/4th of its initial value. If the rate constant for a first -order reation is k, then `t_(1//4)` can be written as

A

0.10/k

B

0.29/k

C

0.69/k

D

0.75/k

Text Solution

Verified by Experts

For a first-order reaction, `t_(1//4) = ((2.303)/(k))log((1)/(1-1//4)) = (0.29)/(k)`
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