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The half-life period of a first-order re...

The half-life period of a first-order reaction is 15 minutes. The amount of substance left after one hour will be,

A

`(1)/(4)` of the original amount

B

`(1)/(8)` of the original amount

C

`(1)/(16)` of the original amount

D

`(1)/(32)` of the original amount

Text Solution

Verified by Experts

Total number of half-lives (n) = `("1 hour")/("15 min") = 4`
Substance left after n half-lives `= ([A]_(0))/((2)^(n))`, Substance remaining after 4 half-lives `= (1)/((2)^(4)) = (1)/(16)`
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