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Ammonia reacts with oxygen giving nitrog...

Ammonia reacts with oxygen giving nitrogen and water. If the rate of formation of `N_(2)` is 0.70 mol `L^(-1) S^(-1)` the rate at which `O_(2)` is consumed is

A

`1.05 mol L^(-1)s^(-1)`

B

`0.70 mol L^(-1)s^(-1)`

C

`2.10 mol L^(-1)s^(-1)`

D

`0.35 mol L^(-1)s^(-1)`

Text Solution

Verified by Experts

The reaction is `4NH_(3) + 3O_(2) rarr 2N_(2) + 6H_(2)O`
`(1)/(2)(d[N_(2)])/(d t) = (1)/(3)(d[O_(2)])/(d t)`. Hence, `-(d[O_(2)])/(d t) = (3)/(2)(d[N_(2)])/(d t) = ((3)/(2)) (0.7 mol L^(-1)s^(-1)) = 1.05 mol L^(-1)s^(-1)`
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