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The half-life for the thermal decomposit...

The half-life for the thermal decomposition of acetone 90s_and is independent of initial concentration of acetone. The time required for the reaction to go to 80% decomposition is (log 2 = 0.30)

A

186.1 s

B

206.1 s

C

150.1 s

D

226.1 s

Text Solution

Verified by Experts

The reaction follows first-order kinetics. Hence `k = 0.693//t_(1//2) = 0.693//(80s)`. For the reaction to be 80%, `[A]_(t)//[A]_(0) = 0.2` Hence
`t = -(2.303 log{[A]_(t)//[A]_(0)})/(k) = ((2.303)(log 2 xx 10^(-1)))/((0.693//80s)) = -((2.303)(0.301-1))/((0.693//80s)) = 186.1`
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