Home
Class 12
CHEMISTRY
For a chemical reaction X rarr Y , the r...

For a chemical reaction X `rarr` Y , the rate of reaction increases by a factor of 1.837 when the concentration of X is increased by 1.5 times, the order of the reaction with respect to X is :

A

1

B

`1.5`

C

2

D

`2.5`

Text Solution

Verified by Experts

`(1.5)^(n) = 1.837, n = (log 1.837)/(log 1.5) = (0.2641)/(0.1761) = 1.5`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the elementary reaction M rarr N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is:

The rate of which reaction increases when the concentration of nitrogen is increased in the manufacture of Ammonia? Forward reaction/Back ward reaction.

For a chemical reaction x A rarr y M the rate law is r=k[A]^3 . If the concentration of (A) is 'doubled the reaction rate will be

Following graph is a plot of the rate of reaction concentration of the reactant. What is the order of the reaction.

Why rate of reaction increases when concentration increases ?

Why rate of reaction increases when surface area increases ?

For a chemicai reaction (A) rarr (B) it is found that the rate of the reaction guadruples when the concentration of (A) is doubled.The rate expression for the reaction is rate =(k)[(A)] (n) , where the value of (n) is a)1 b)2 c)0 d)3

When the concentration of a reactant in reaction A rarr B is increased by 8 times but rate increases only 2 times, the order of the reaction would be