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The reaction A rarrB+C has rate constan...

The reaction `A rarrB+C` has rate constant `1xx10^(-3) Ms^(-1)`. If one starts the reaction with one mole of A then `t_(1//2)` and completion of reaction time would be:

A

1000 s, 500 s

B

500 s, 1000 s

C

750 s, 400 s

D

400 s, 800 8

Text Solution

Verified by Experts

This is zero order reaction from the values of `K(Ms^(-1))`
`therefore t_(1//2) = ((A_(0)))/(2K) = (1)/(2 xx 10^(-3)) = 500sec` and `t_(1//2) = ([A]_(0))/(K) = (1)/(10^(-3)) =1000 sec`
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