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A reactant (A) forms two products (Assum...

A reactant (A) forms two products (Assume that `A_(1) = A_(2)` , which are pre-exponential factor)
`A overset(k_(1)) to B`, Activation energy `E_(a1)`
`A overset(k_(2)) to C`, Activation energy `E_(a2)`
If `E_(a2) = 2E_(a1)`, then `k_(1)` and `k_(2)` are related as:

A

`k_(2) = k_(1)e^(-E_(a_(1))/RT)`

B

`k_(2) = k_(1)e^(-E_(a_(2))/RT)`

C

`k_(1) = A k_(2)e^(-E_(a_(1))/RT)`

D

`k_(1) = 2k_(2)e^(-E_(a_(2))/RT)`

Text Solution

Verified by Experts

`k_(2) = Ae^(-E_(a_(1))//RT), K_(t) = Q e^(-E_(a_(1))//RT), therefore (k_(2))/(k_(1)) = e^((-E_(a2) + E_(a1))RT)`
`(k_(2))/(k_(1)) = e^(E_(a_(1))//RT)` Since, `E_(a_(2)) = 2E_(a_(1)) " "k_(2) = k_(1)e^(-E_(a_(1))//RT)`
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