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For a reaction A rarr Product half-lif...

For a reaction A `rarr` Product half-life measured for two different value of intial concentration `5xx10^(-3)` M and `25 xx10^(-4)` M are 1.0 and 8.0 hrs respectively. If initial concentration is adjusted to `1.25 xx10^(-3)` M, the new half-life would be

A

16 hrs

B

32 hrs

C

64 hrs

D

256 hrs

Text Solution

Verified by Experts

For a `n^(th)` order reaction : `t_(1//2) prop (1)/(a_(n-1)) : a = 1` initial concentration
`rArr ((5 xx 10^(-3))/(25 xx 10^(-4)))^(n-1) = ((8)/(1)) rArr ((5 xx 10^(-3))/(1.25 xx 10^(-3)))^(n=4) = (t_(1//2))/(1) rArr t_(1//2) = 64 hrs`
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