In a certain reaction, 10% of the reactant decomposes in one hour, 20% in two hours, 30% in three hours, and so on. The dimension of the velocity constant (rate constant) are

Options

A. `h r^(-1)`
B. `mol L^(-1) h r^(-1)`
C. `L mol^(-1) s^(-1)`
D. `mol^(-1) s^(-1)`

Explanation

From the question, it is clear `t_(1//2) prop a`. Hence, zero order reaction. So, dimension of `k = mol L^(-1) hr^(-1)`.
For zero order : `t = (x)/(k)` or `k = (x)/(t)`
If `t = t_(10%) = 10 "min", x = 10` then , `k = (10)/(10) = 1 mol L^(-1) r^(-1)`
If `t = t_(20%) = 20 "min", x = 20`, then, `k = (20)/(20) = 1 mol L^(-1) t^(-1)`.
Similarly, for 30% and so on, Thus, reaction is zero order.