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For the reaction A+B rarr C+D doubling...

For the reaction A+B `rarr` C+D doubling the concentration of both the reactants increases the reaction rate by eight times and doubling the concentration of only B simply doubles reaction the rate law is given as

A

`r = k[A]^(1//2)[B]^(1//2)`

B

`r = k[A][B]^(2)`

C

`r = k[A]^(2)[B]`

D

`r = [A][B]`

Text Solution

Verified by Experts

The correct Answer is:
C
Given that `r = k[A]^(x)[B]^(y)` ….(1) `8r = k[2A]^(x)[2B]^(y)` …..(2) `2r = k[A]^(x)[2B]^(y)` ……(3)
On dividing Eq. (1) by Eq. (3), we get = 1, and on dividing Eq. (2) by Eq. (3), we get x = 2. So, the reaction is `r = k[A]^(2)[B]`.
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