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For the reaction 2N(2)O(5)rarr4NO(2)+O(...

For the reaction `2N_(2)O_(5)rarr4NO_(2)+O_(2)` the rate equation can be express as
`(d[N_(2)O_(5)])/(dt)=k[N_(2)O_(5)` and `(d[NO_(2)])/(dt)=k'[N_(2)O_(5)]` k and k' are related as

A

k = k'

B

2k = k'

C

k = 2k'

D

k = 4k'

Text Solution

Verified by Experts

The correct Answer is:
B
For the reaction, `2N_(2)O_(5) hArr 4NO_(2) + O_(2)`
The rate law is rate `= -(1)/(2)(d[N_(2)O_(5)])/(d t) = (1)/(4)([NO_(2)])/(dt) = (d[O_(2)])/(d t) = k[N_(2)O_(5)]`
`(-d[N_(2)O_(5)])/(dt) = 2k[N_(2)O_(5)] " "(-d[N_(2)O_(5)])/(d t) = k_(1)[N_(2)O_(5)]`
`k_(1) = 2k, " "k_(2) = 4k , " "2k_(1) = k_(2) = 2k = k.`
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