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At the intersection point of two curves ...

At the intersection point of two curves `n A rarr m B`, the concentration of B can be given by assume first order :

A

`(m)/(m+n)[A]_(0)`

B

`(m)/(n)[A_(0)]`

C

`(m)/(m-n)[A_(0)]`

D

`(n)/(m+n)[A_(0)]`

Text Solution

Verified by Experts

The correct Answer is:
A
`[A]_("left") = [B]_("formed") = (m)/(n)[A]_("decayed"), [A_(0)] e^(-lambda t) = (m)/(n) [1=e^(-lambda t)][A_(0)]`
`therefore n e^(-lambda t) = m - m e^(-lambda t)` or `r^(-lambda t) = (m)/(m+n)`
`therefore [B]_("formed") = (m)/(n)[1-(m)/(m+n)][A_(0)] = (m)/(n)[(m+n-m)/(m+n)][A_(0)] = (m)/(m+n)[A_(0)]`
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