For a reaction `A rarr` Product, [A] is plotted against time as shown in the following figure :

The rate of reaction after reaction aftr 15 min is

Options

A. `1.2 xx 10^(-4) M "min"^(-1)`
B. `2.67 xx 10^(-4) M "min"^(-1)`
C. `6.67 xx 10^(-4) M "min"^(-1)`
D. `1.33 xx 10^(-4) M "min"^(-1)`

Answer

D

Explanation

Since the graph is not linear, so, average rate and instantaneous rates are different.
Here we need to calculate instantaneous rate after 15 min. For the given reaction, Rate `= -(d[A])/(d t)` which is indicated by the slope of the graph at point P. The slope can be calculated by drawing tangent line at point P. we need two points on this tangent line to find the slope.
The two points are (0, 0.03) and (15, 0.01). Therefore, Rate `= -(0.01-0.03)/(15-0) = 1.33 xx 10^(-3) M "min"^(-1)`