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The rate constant for a first order reac...

The rate constant for a first order reacion is `3.2 xx 10^(-5) s^(-1)` at a particular temperature. What percentage of reactants will react on heating for 1.5 h ?

A

`16.5%`

B

`20.3%`

C

`19.2%`

D

`15.9%`

Text Solution

Verified by Experts

The correct Answer is:
D
For a first-order reaction, the integrated rate law is given by
`k t = ln""([A_(0)])/([A]_(t)) = 2.303 log""([A_(0)])/([A]_(t)) rArr k = (2.303)/(t) log""([A]_(0))/([A]_(t))` Substituting the given values in the rate law equation, we get `3.2 xx 10^(-5)s^(-1) = (2.303)/(1.5 xx 60 xx 60s)log""(a)/(a-x)`
`log""(a)/(a-x) = 1.1885 rArr a = 1.1885a - 1.1885 x`
`1.1885 x = 1.1885a - a = 0.1885 a, (x)/(a) = (0.1885)/(1.1885) = 0.159 = 15.9%`
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