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The rate constant of a reaction is given...

The rate constant of a reaction is given by , `k = 2.1 xx 10^(10)` exp (-2700/RT). It means that,

A

log k vs. 1/T will be a straight line with slop = -2700/2.303 R.

B

log k vs. 1/T will be straight line with intercept on log k axis `= 2.1 xx 10^(10)`.

C

the number o effective collisions is `2.1 xx 10^(10) cm^(-3)s^(-1)`.

D

half-life of the reaction increases with increases of temperature

Text Solution

Verified by Experts

The correct Answer is:
A, B
According to Arrhenius equation , `k = A e^(-E_(a)//RT)`
Therefore, log k = log A `- (E_(a))/(2.303 RT) rArr log k = 2.1 xx 10^(10) - (2700 xx 1)/(2.303 RT)`
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