Starting with one mole of a compound A, it is found that the reaction is 3/4 completed in 1 hour. Calculated the rate constant if the reaction if the reaction is of II order.

Answer

3

Explanation

Given , a = 1 mole, x = 3/4 mole t = 1 hr
`K = (1)/(t xx a).(x)/((a-x)) = (1)/(1xx 1).(3)/(4(1-(3)/(4))) = 3, K = 3 L mol^(-1)h r^(-1)`