During hydrolysis of ester is acidic medium ester `+ H_(2)O overset(H^(+))rarr` acid + alcohol rate law is given as r = k[ester] `[H^(+)]` and volume of base used at difference time intervals is given as at pH = 3
`{:("t (in sec)",0,10,oo),(V_(b) "(in mL)",50,100,150):}`
For same initial concentration of ester and at same temperature, volume of base and used when 50% of ester will be hydrolysis at pH = 4 :

Options

A. 100 mL
B. 65 mL
C. 55 mL
D. 45 mL

Answer

C

Explanation

At pH = 4, `V_(0) = 5mL`
`rArr (a)/(a-x) = (V_(oo) - V_(0))/(V_(oo) - V_(t)) = 2 rArr (100)/(105 - V_(t)) =2 rArr V_(t) = 10.5 - 50 = 55 mL`