If C,R,L and I denot capacity resitance, inductance and electric current respecitively, the quantities having the same dimensions of time are (a) CR , (b) L//R , (c) sqrt(L//C) , (d) LI^(2)
Let [in_(0)] denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:
L4 To L6 Current Electricity
Tutorial on L1 to L3 of Current Electricity
The magnetic energy stored in an inductor is given by E=1/2L^(a)l^(b) . Find the value of 'a' and 'b' . Here L= self-inductance l= electric current.
Using mass (M) , length (L) , time (T) , and electric current (A) as fundamental quantities , the dimensions of permitivity will be
If M = mass, L = length, T = time and I = electric current, then the demensional formula of resistance R will be given by
