Refer to the circuit diagram and the corresponding graphs. The current rises when key K is pressed. With R= R_(1) and L=L_(1) the rise of current is shown by curve(1), while curve(2) shows the rise of current when R=R_(2) and L = L_(2) . The maximum current is same for both curves, then:
If C,R,L and I denot capacity resitance, inductance and electric current respecitively, the quantities having the same dimensions of time are (a) CR , (b) L//R , (c) sqrt(L//C) , (d) LI^(2)
Let [in_(0)] denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:
Find current in R , L and 2L in steady state.
The voltage-current graphs for two resistor of the same meterial and the same radius with lengths, L_1 and L_2 are shown in fig 5.2. if L_1 gt L_2 , state with reason which of these graphs represents votage- current change of L_1.
Two inductors L_(1) and L_(2) are connected in parallel and a time varying current flows as shown. the ratio of current i-(1)//i_(2)
L4 To L6 Current Electricity
Tutorial on L1 to L3 of Current Electricity
The magnetic energy stored in an inductor is given by E=1/2L^(a)l^(b) . Find the value of 'a' and 'b' . Here L= self-inductance l= electric current.
Using mass (M) , length (L) , time (T) , and electric current (A) as fundamental quantities , the dimensions of permitivity will be
