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CURRENT ELECTRICITY - L8

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Let [in_(0)] denote the dimensional formula of the permittivity of vacuum. If M= mass, L=length, T=Time and A= electric current, then:

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The magnetic energy stored in an inductor is given by E=1/2L^(a)l^(b) . Find the value of 'a' and 'b' . Here L= self-inductance l= electric current.

Using mass (M) , length (L) , time (T) , and electric current (A) as fundamental quantities , the dimensions of permitivity will be