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If m^2+m'^2+ 2mm' cos theta =1, n^2+n'^2...

If `m^2+m'^2+ 2mm' cos theta =1, n^2+n'^2+2 n n' cos theta =1` and `mn+m'n’ +(mn’ +m’n) cos theta=0`, prove that `m^2+ n^2= cosec^2 theta`.

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MODERN PUBLICATION-TRIGNOMETRY-EXERCISE
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