Explain
why most electrons are emitted with kinetic energy less than the maximum.

In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 A. (a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton. (b) What is the minimum work required to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)?

In the explanation of photoelectric effect, we assume one photon of frequency v collidies with an electron and transfers its energy. This leads to the equation for the maximum energy E_max of the emitted electron as E_max=hv-phi_0 Where phi_0 is the work function of the metal. if an electron absorbs 2 photons (each of frequency v) what will be the maximum energy for the emitted electron?

In an oscillating pendulum, at what positions are the potential and kinetic energy maximum.

The work function of caesium metal is 2.14 eV. When light of frequency 6 xx 10^14 Hz is incident on the metal surface, photomission of electrons occurs. What is the maximum kinectic energy of the emitted electrons.

State if each of the following statements is true or false. Give reasons for your answer:- In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system.

What is the stopping potential of a photocell, in which electrons with a maximum kinetic energy of 6eV are emitted?