Work function of a photosensitive metla is 1,875 e V.Calculate the waveelength of incident light ,which will just cause the emission of photoelectrons.

Work function of a photosensitive metal is 1.875 eV. Calculate the wavelength of incident light, which will just cause the emission of photoelectrons.

The work function of sodium is 2.3 eV. Calculate the maximum wavelength for the light that will cause photoelectrons to be emitted from sodium.

The work function of caesium metal is 2.14 eV. When light of frequency 6 xx 10^14 Hz is incident on the metal surface, photomission of electrons occurs. What is the maximum speed of the emitted photoelectrons?

In a photoelectric effect set up, a point source of light of power 3.2 xx10^(-3) W emits monoenergetic photons of energy 5eV.The source is located at a distance of a stationary metallic sphere of work function 3eV and radius 8xx10^(-3)m .The efficiency of photoelectron emission is one for every 10^(6) incident photons.Assume that the sphere is isolated and initially neutral and the photoelectrons are initially swept away after emission. Find the ratio of the wavelength of incident light to the de Broglie wavelength of the fastest phtotelectrons emitted.

Light of wavelength 6,000 overset @A is incident on a thin film of refractive index 1.5 ,such that angle of refraction into the film in 60^@ .Calculate the smallest thickness of the film,which will make it appear dark by reflection.

Ultraviolet light is incident on two photosensitive materials, having work functions W_1 and W_2 , where W_1 > W_2 . In which case will the kinetic energy of emitted electrons be greater? Why?