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If x^4+x^2y^2+y^4=21 and x^2+xy+y^2= 7, ...

If `x^4+x^2y^2+y^4=21` and `x^2+xy+y^2= 7`, then the value of `(1/x^2+1/y^2)` is :
यदि `x^4+x^2y^2+y^4=21` तथा `x^2+xy+y^2= 7` है, तो `(1/x^2+1/y^2)` का मान होगा :

A

`5//2`

B

`7//4`

C

`7//3`

D

`5//4`

Text Solution

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The correct Answer is:
D
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