Dielectric Inserted With Battery Connected and Removed

Dielectric|Capacitors Without Battery

A parallel plate capacitor is charged by a battery. After some time the battery is disconnected and a dielectric slab of dielectric constant K is inserted between the plates. How would (i) the capacitance, (ii) the electric field between the plates and (iii) the energy stored in the capacitor, be affected ? Justify your answer.

A parallel plate capacitor (without dielectric) is charged by a battery and kept connected to the battery. A dielectric salb of dielectric constant 'k' is inserted between the plates fully occupying the space between the plates. The energy density of electric field between the plates will:

When dielectric is inserted in the space between plates of a capacitor, then

A parallel plate capacitor is connected to a battery and inserted a dielectric plate between the place of plates then which quantity increase

Dielectric||Capacitance with Dielectric||Dielectric with Battery and Without Battery

A capacitor with no dielectric is connected to a battery at t=0.Consider a point A in the connecting wires and a point B in between the plates.