`V_2O_3` and `CrO` respectively are

Options

A. Acidic & basic
B. Basic & basic
C. Basic & acidic
D. Amphoteric and Basic

Answer

To determine the nature of the oxides \( V_2O_3 \) and \( CrO \), we need to analyze the oxidation states of the metal ions in each compound and relate them to their acidic or basic character.

### Step-by-Step Solution:

1. **Identify the Oxidation State of Vanadium in \( V_2O_3 \)**:
- The formula for \( V_2O_3 \) indicates there are 2 vanadium (V) atoms and 3 oxygen (O) atoms.
- The oxidation state of oxygen is typically \(-2\).
- Setting up the equation for the total charge:
\[ 2x + 3(-2) = 0 \]
where \( x \) is the oxidation state of vanadium.
- Simplifying gives:
\[ 2x - 6 = 0 \implies 2x = 6 \implies x = +3 \]
- Thus, the oxidation state of vanadium in \( V_2O_3 \) is \( +3 \).

2. **Identify the Oxidation State of Chromium in \( CrO \)**:
- The formula for \( CrO \) indicates there is 1 chromium (Cr) atom and 1 oxygen (O) atom.
- Again, the oxidation state of oxygen is \(-2\).
- Setting up the equation for the total charge:
\[ x + (-2) = 0 \]
- Simplifying gives:
\[ x - 2 = 0 \implies x = +2 \]
- Thus, the oxidation state of chromium in \( CrO \) is \( +2 \).

3. **Determine the Nature of the Oxides**:
- The general rule for the nature of metal oxides based on oxidation states is:
- Low oxidation state (typically \( +1 \) or \( +2 \)) indicates basic character.
- Medium oxidation state (typically \( +3 \) or \( +4 \)) can indicate amphoteric character.
- High oxidation state (typically \( +5 \) and above) indicates acidic character.
- For \( V_2O_3 \) with \( +3 \) oxidation state, it can show amphoteric character but is generally considered basic due to the presence of lower oxidation states.
- For \( CrO \) with \( +2 \) oxidation state, it is basic.

4. **Conclusion**:
- Both \( V_2O_3 \) and \( CrO \) are basic in nature.
- Therefore, the correct answer is **Option B: Basic and Basic**.