Find `y(pi)` if `y(0)=7 and (dy)/dx=2(y-2sinx-10)x+2cosx`

ysinx dy/dx=(sinx-y^2)cosx

Find (dy)/(dx) , if y=(sinx)^(cosx)

Let y=y(x) be the solution of the differential equation (dy)/(dx)=2(y+2sinx-5)x-2cosx such that y(0)=7 . Then y(pi) is equal to

Find (dy)/(dx) , when: y=(sinx)^(cosx)

Find dy/dx y=x^(7/2)

(dy)/(dx) = y tan x - 2 sinx

y=2^sinx . Find dy/dx