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A man walks 10 km in the east direction ...

A man walks 10 km in the east direction and then turns to the right and moves 5 km in that direction. Then, he takes a left turn and moves 2 km ahead. Find the minimum distance between his initial and final position.

A

12 km

B

13 km

C

7 km

D

18 km

Text Solution

Verified by Experts

The correct Answer is:
B

`AD = sqrt((AE)^(2) + (DE)^(2))`
` = sqrt((12)^(12) + (5)^(2)) `
` = sqrt(144 + 25)`
` = sqrt(169) ` = 13 km
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