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If sec theta= 8x and tan theta=8/x (x ne...

If `sec theta= 8x` and `tan theta=8/x (x ne 0)`, then the value of `16(x^2-1/x^2)` is:

A

`1/2`

B

`(1)/(16)`

C

`1/4`

D

`1/3`

Text Solution

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The correct Answer is:
C
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