In a triangle ABC, PQ is a straight line parallel to AC, such that Area ABC : Area PBQ = 3:1. Then CB : CQ is equal to:

Options

A. `(sqrt3-2)/(2)`
B. `(sqrt3)/(2)(sqrt3-1)`
C. `(sqrt3)/(2)`
D. `(sqrt3)/(2)(sqrt3+1)`

Answer

D