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In a triangle ABC, AD is perpendicular t...

In a `triangle ABC`, AD is perpendicular to BC from A, if `angle BAC = 90^@`, then `AB^2:AC^2` is equal to :

A

`BD ^(2) : CD ^(2)`

B

`CD : BD`

C

`CD ^(2) : BD ^(2)`

D

`BD : CD`

Text Solution

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The correct Answer is:
D
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