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If the numerator of a fraction is increa...

If the numerator of a fraction is increased by 15% and denominator is decreased by 20%, then the fraction, so obtained, is `17/65`. What is the original fraction?

A

`281/1495`

B

`278/1495`

C

`267/1495`

D

`272/1495`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's denote the original fraction as \( \frac{n}{d} \), where \( n \) is the numerator and \( d \) is the denominator. ### Step 1: Express the changes in the numerator and denominator The problem states that the numerator is increased by 15% and the denominator is decreased by 20%. - The new numerator after the increase is: \[ n + 0.15n = 1.15n \] - The new denominator after the decrease is: \[ d - 0.20d = 0.80d \] ### Step 2: Set up the equation based on the new fraction According to the problem, the new fraction equals \( \frac{17}{65} \). Therefore, we can write the equation: \[ \frac{1.15n}{0.80d} = \frac{17}{65} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ 1.15n \cdot 65 = 17 \cdot 0.80d \] ### Step 4: Simplify the equation Calculating the left side: \[ 1.15 \cdot 65 = 74.75 \] So the equation becomes: \[ 74.75n = 13.6d \] ### Step 5: Rearrange the equation to express \( \frac{n}{d} \) We can rearrange the equation to find the ratio \( \frac{n}{d} \): \[ \frac{n}{d} = \frac{13.6}{74.75} \] ### Step 6: Simplify the fraction Now we simplify \( \frac{13.6}{74.75} \): To simplify, we can multiply both the numerator and denominator by 100 to eliminate the decimals: \[ \frac{1360}{7475} \] Now we can divide both by 5: \[ \frac{272}{1495} \] ### Step 7: Final result Thus, the original fraction \( \frac{n}{d} \) is: \[ \frac{272}{1495} \]
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