A particle under the action of a force has a period of `3s` and under the action of another force it has a period `4sec` in `SHM`. What will be its period under the combined action of both forces in the same direction?

A particle under the action of one SHM has a period of 3 s and under the effect of another it has a period 4s. Its time period under the combined action of both the SHM's in the same direction is (0.4x)second. Find value of x?

A particle under the action of one SHM has a period of 3 s and under the effect of another it has a period 4s. Its time period under the combined action of both the SHM's in the same direction is (0.4x)second. Find value of x?

Which does not change under the action of force

For a body to be in equilibrium under the combined action of several forces

For a body to be in equilibrium under the combined action of several forces

A body under the action of several forces will have zero acceleration

A body executing S.H.M. has a period of 3 s under one force and 4 s under another force. Then time period under the action of both the forces together in the same direction is

Under the action of variable force, at any instant the displacement is

Under the action of variable force, at any instant the displacement is