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A bag contains 10 rupees, 2 rupees and 1...

A bag contains 10 rupees, 2 rupees and 1 rupee coins. The value of 10 rupees, 2 rupees and 1 rupee coins are in the ratio of 15 : 8 : 1 respectively. If total number of coins is 273, then what will be the total value (in Rs) of all coins?

A

1008

B

924

C

1102

D

1218

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information given in the question and the ratios provided. ### Step 1: Understand the Ratios We know the values of the coins are in the ratio of 15:8:1 for 10 rupee, 2 rupee, and 1 rupee coins respectively. ### Step 2: Define Variables Let: - The value of 10 rupee coins = 15x - The value of 2 rupee coins = 8x - The value of 1 rupee coins = 1x ### Step 3: Total Value Calculation The total value of all coins can be expressed as: \[ \text{Total Value} = 15x + 8x + 1x = 24x \] ### Step 4: Relate Value to Number of Coins Next, we relate the values to the number of coins: - Let the number of 10 rupee coins = \( \frac{15x}{10} = \frac{3x}{2} \) - Let the number of 2 rupee coins = \( \frac{8x}{2} = 4x \) - Let the number of 1 rupee coins = \( \frac{1x}{1} = x \) ### Step 5: Total Number of Coins The total number of coins is given as 273: \[ \frac{3x}{2} + 4x + x = 273 \] ### Step 6: Simplify the Equation To simplify, we first convert all terms to have a common denominator: \[ \frac{3x}{2} + \frac{8x}{2} + \frac{2x}{2} = 273 \] Combining the fractions gives: \[ \frac{3x + 8x + 2x}{2} = 273 \] \[ \frac{13x}{2} = 273 \] ### Step 7: Solve for x To eliminate the fraction, multiply both sides by 2: \[ 13x = 546 \] Now, divide by 13: \[ x = 42 \] ### Step 8: Calculate Total Value Now that we have \( x \), we can find the total value: \[ \text{Total Value} = 24x = 24 \times 42 = 1008 \] ### Final Answer The total value of all coins is **Rs. 1008**. ---
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