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P and Q are two alloys which are prepare...

P and Q are two alloys which are prepared by mixing tin and lead in the ratio of 12 : 5 and 4 : 3 respectively. If equal quantities of alloys are melted to form a third alloy R, then what is the ratio of tin and lead in alloy R?

A

84 : 65

B

57 : 35

C

76 : 43

D

78 : 47

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of tin and lead in alloy R formed by melting equal quantities of alloys P and Q, we can follow these steps: ### Step 1: Understand the Ratios of Alloys P and Q Alloy P is made of tin and lead in the ratio of 12:5. This means for every 12 parts of tin, there are 5 parts of lead. Alloy Q is made of tin and lead in the ratio of 4:3. This means for every 4 parts of tin, there are 3 parts of lead. ### Step 2: Define Equal Quantities for Mixing Let’s assume we take 1 unit of each alloy for mixing. This will help us maintain equal quantities of both alloys. ### Step 3: Calculate the Amount of Tin and Lead in Alloy P For alloy P (12:5): - Total parts = 12 + 5 = 17 parts - Amount of tin = (12/17) * 1 unit = 12/17 units - Amount of lead = (5/17) * 1 unit = 5/17 units ### Step 4: Calculate the Amount of Tin and Lead in Alloy Q For alloy Q (4:3): - Total parts = 4 + 3 = 7 parts - Amount of tin = (4/7) * 1 unit = 4/7 units - Amount of lead = (3/7) * 1 unit = 3/7 units ### Step 5: Find a Common Denominator To add the amounts of tin and lead from both alloys, we need a common denominator. The least common multiple of 17 and 7 is 119. ### Step 6: Convert Amounts to Common Denominator Convert the amounts of tin and lead to have a common denominator of 119: - For alloy P: - Tin: (12/17) = (12 * 7)/(17 * 7) = 84/119 units - Lead: (5/17) = (5 * 7)/(17 * 7) = 35/119 units - For alloy Q: - Tin: (4/7) = (4 * 17)/(7 * 17) = 68/119 units - Lead: (3/7) = (3 * 17)/(7 * 17) = 51/119 units ### Step 7: Add the Amounts of Tin and Lead Now, we can add the amounts of tin and lead from both alloys: - Total tin = 84/119 + 68/119 = (84 + 68)/119 = 152/119 units - Total lead = 35/119 + 51/119 = (35 + 51)/119 = 86/119 units ### Step 8: Form the Ratio of Tin to Lead in Alloy R Now, we can form the ratio of tin to lead in alloy R: - Ratio of tin to lead = Total tin : Total lead = 152 : 86 ### Step 9: Simplify the Ratio To simplify the ratio, we can divide both sides by 2: - 152 ÷ 2 = 76 - 86 ÷ 2 = 43 Thus, the ratio of tin to lead in alloy R is **76 : 43**.

To solve the problem of finding the ratio of tin and lead in alloy R formed by melting equal quantities of alloys P and Q, we can follow these steps: ### Step 1: Understand the Ratios of Alloys P and Q Alloy P is made of tin and lead in the ratio of 12:5. This means for every 12 parts of tin, there are 5 parts of lead. Alloy Q is made of tin and lead in the ratio of 4:3. This means for every 4 parts of tin, there are 3 parts of lead. ### Step 2: Define Equal Quantities for Mixing ...
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