Home
Class 14
GENERAL KNOWLEDGE
The mass of moon is (1)/(81) of earth 's...

The mass of moon is `(1)/(81)` of earth 's mass and its radius is `(1)/(4)` of that of earth .If the escape velocity from the earth 's surface is 11.2km/s , is value for the moon is :

A

0.14 km/s

B

0.5 km/s

C

2.5 km/s

D

5.0 km/s

Text Solution

Verified by Experts

The correct Answer is:
c
Promotional Banner

Similar Questions

Explore conceptually related problems

The mass of the moon is 7//81 th of earth 's mass and its radius is 1//4 th that of the earth if the escape velocity from the earth surface is 11.2 kms^(-1) its value for the moon will be

Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon is

Mass of moon is 1//81 time that of earth and its radius is 1//4 the earth's radius. If escape velocity at surface of earth is 11.2 km/s , then its value at surface of moon is

The moon has a mass of (1)/(81) that of the earth and radius of (1)/(4) that of the earth. The escape speed from the surface of the earth is 11.2 km // s. The escape speed from surface of the moon is-

The mass of planet mars is 1/10 th of the mass of earth and radius is 1/2 of the radius of earth. If the scape velocity at the earth is 11.2km/s, then the scape velocity at Mars will be

The mass of a planet is four times that of the earth and its radius is double the radius of earth . The escape velocity of a body from the earth is 11.2xx 10^(3) m/s. Find the escape velocity of a body from the plant .

For moon, its mass is 1/81 of earth mass and its diameter is 1/3.7 of earth dia. If acceleration due to gravity at earth surface is 9.8 m//s^2 then at moon its value is :

The mass of the earth is 9 times that of the mars. The radius of the earth twice that of the mars. The escape velocity of the earth is 12km//s . The escape velocity on the mars is ........ km//s

Jupiter has a mass 320 times that of the earth and its readius is 11.2 times that of the earth. Determine the escape velocity from the surface of jupiter, given that the escape velocity from the surface of earth is 11.2 km s^(-1) .

The mass of the moon is 1/81 of the earth but the gravitational pull is 1/6 of the earth. It is due to the fact that

Recommended Questions
  1. The mass of moon is (1)/(81) of earth 's mass and its radius is (1)/(4...

    Text Solution

    |

  2. जैव-विकास क्या है? इसके समर्थन में जीवाश्म विज्ञानं तथा भूर्ण विज्ञानं...

    Text Solution

    |

  3. ओजोन पर्त की हानि पहुंचाने वाले प्रदूषको का विवरण दीजिए । पृथ्वी पर...

    Text Solution

    |

  4. m द्रव्यमान का कण जिस पर आवेश q है, एकसमान चुम्बकीय क्षेत्र B के लम्ब...

    Text Solution

    |

  5. एक इलेक्ट्रॉन 6 xx 10 ^ (7 ) मी/से वेग से एकसमान चुम्बकीय क्षेत्र जिस...

    Text Solution

    |

  6. एक परमाणु में एक इलेक्ट्रॉन नाभिक के चारों ओर 6.6 xx 10 ^(4 ) मी/से के...

    Text Solution

    |

  7. पृथ्वी के उत्तरी व दक्षिणी ध्रुवों (चुम्बकीय ध्रुवों) पर नमन कोण का मा...

    Text Solution

    |

  8. k के किन मान (मानों) के लिये समीकरण निकाय संगत है? 2x - 4y = k 5x...

    Text Solution

    |

  9. एक फलक केंद्रित घनीय तत्व (परमाणु द्रव्यमान = 60) की कोर लम्बाई 400 pm...

    Text Solution

    |