Home
Class 14
MATHS
AB is a line and P is its midpoint. D an...

AB is a line and P is its midpoint. D and E are two points on the same side of line segment AB such that `angleBAD=angleABE and angleEPA=angleDPB`. Prove that
`DeltaDAP-=DeltaEBP`

Promotional Banner

Topper's Solved these Questions

  • CONGRUENCE AND SIMILAR TRIANGLES

    LUCENT PUBLICATION|Exercise EXERCISE-5A|47 Videos

  • CONGRUENCE AND SIMILAR TRIANGLES

    LUCENT PUBLICATION|Exercise EXERCISE-5B|8 Videos

  • CIRCLE AND ITS TANGENT LINES

    LUCENT PUBLICATION|Exercise EXERCISE 8B|27 Videos

  • ELEMENTARY TRIGONOMETRIC IDENTITIES

    LUCENT PUBLICATION|Exercise EXERCISE 11B|37 Videos

Similar Questions

Explore conceptually related problems

AB is a line and P is its midpoint. D and E are two points on the same side of line segment AB such that angleBAD=angleABE and angleEPA=angleDPB . Prove that AD=BE

AB is a line segment and P is its midpoint. D and E are points on the same side of AD such that angleBAD=angleABE and angleEPA=angleDPB . Show that (i) DeltaDAP~=DeltaEBP, (ii) AD=BE.

AB is a line segment D and P is its mid-point. D and E are points on the same side of AB such that angleBAD = angleABE and angleEPA = angleDPB (see figure). Show that DeltaDAP~=DeltaEBP

AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that angleBAD = angleABE and angleEPA = angleDPB (see figure). Show that AD=BE

AB is a line segment, AX and BY are two equal line segments drawn on opposite sides of line AB such that AX || BY. If AB and XY intersect each other at P, prove that DeltaAPX~=DeltaBPY

In Fig.9.24, ABC and ABD are two triangles on the same base AB.If line- segment CD is bisected by AB at O,show that

AB is a line segment.AX and BY are two equal line segments drawn on opposite sides of line AB such that AX||BY If AB and XY intersect each other at P, prove that APX~=BPY( ii) AB and XY bisect each other.

If C and D are the points of internal and external division of line segment AB in the same ratio, then AC,AB, AD are in

In the figure ABCD is a trapezium in which side AB is parallel to side DC and E is the midpoint of side AD.If F is a point on the side BC such that the line segment EF is parallel to DC.Prove that Fis the mid-point of B BC and EF=(1)/(2)(AB+DC)